1st-year Chemistry Chapter 3 Notes Short / Long Questions pdf

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 Looking for the 11th beauty Chemistry financial ruin 3 Gases notes? Here we have got shared the primary 12  Chemistry Chapter 3 Short Questions Notes.


1st-year Chemistry Chapter 3 Notes Short and Long Questions pdf
1st-year Chemistry Chapter 3 Notes Short and Long Questions pdf


1st-year Chemistry Chapter three Notes Short Questions

01. The plot of PV, rather than P, is a right away line at a regular temperature and with a tough and rapid huge sort of moles of an outstanding fueloline.

This directly-line indicates that at regular immoderate temperature, the amount increase and price of product PV need to develop due to an increase of amount at the identical stress, but, PV remains regular.

 02. The direct line in (above graph) is parallel to the stress axis and goes a long way from the stress axis at higher pressures for plenty of gases.


 When immoderate stress is executed to fueloline then repulsion, similarly to attractive forces, seems to be dominant in some fueloline molecules. So to this degree fueloline doesn’t behave ideally so the street goes a long way from the stress axis at immoderate stress.

 03. H2 and He are best at room temperature but SO2 and Cl2 at the moment are not. Explain.


 Both SO2 and Cl2 have strong intermolecular forces in them due to greater period and further polarizability.




 The strain of attraction in line with unit amount might be very immoderate in the end excluded amount (detail b) is also immoderate. That is why they behave non-best at room temperature.

 04. Water vapors do now not behave ideally at 273o C. Explain.


 At this temperature, water vapors can be converted into liquids through manner of the method of utilizing stress.

 05. SO2 is enormously non-best at 273K but behaves ideally at 327oC.


 Gases behave ideally at immoderate temperature and espresso stress. When the temperature of SO2 is stepped forward with the aid of using 273K to 327oC, the intermolecular forces are decreased and fueloline becomes greater best.

 06. Throw some moderate on the detail 1/273 in Charle’s law.


 The detail 1/273 in Charle’s law might be very important. Because the amount of a given mass of a fueloline will grow or lower through manner of the method of 1/273 of its precise amount at 0°. The equation this is used to calculate the amount of a fueloline at any temperature is:

 Vt = Vo (1+t/273)

07. Why enjoy comfortably in gases withinside the devices of g dm−3 in the location of g cm−3, a unit this is used to specify the densities of liquids and solids?


Gas density is expressed in g dm−3 even as the density of liquids and solids is expressed in g cm−3. the density of CH4 at 0°C and 1 atm is 0. 71 g dm−3, but, if it's far expressed in g cm−3, then it's far 0.00071. so if densities of gases are expressed in g dm−3 then, the answer is reasonably-priced but even as expressed in g cm−3 then, the answer might be very small and may work the fourth vicinity of decimal for some gases.

 08. Do you observe that 1 mole of H2 and 1 mole of NH3 at 0°C and 1 atm-stress should have Avogadro’s huge sort of particles?


 1 mole of H2 and 1 mole of NH3 at 0°C and 1 atm-stress need to occupy 22.414 dm3 amount and so every one of these gases needs to have identical Avogadro’s huge sort of particles.

 09. How are you capable of delivering a reason behind that plasma as a whole is unbiased?


 Plasma can be created through manner of the method of ionizing the fueloline mixture, that is consisting of ions, electrons, and unbiased atoms. Although plasma includes electrons and ions and conducts energy it's far macroscopically unbiased. Because in measurable quantities the huge sort of electrons and ions is the same.

10. Justify that 1 cm3 of H2 and 1 cm3 of CH4 at STP should have a similarly huge sort of molecules even as one molecule of CH4 is 8 times heavier than that of hydrogen.


 According to Avogadro’s Law: “Equal volumes of all the proper gases at the identical temperature and stress incorporate a same huge sort of molecules”. So 1 cm3 of H2 and 1 cm3 of CH4 at STP should have a similarly huge sort of molecule. No doubt, 1 cm3 of CH4 is 8 times heavier than that of hydrogen, but, this doesn’t disturb the amount occupied. Because at STP one molecule of the fueloline is at a distance of 3 hundred times its very very own diameter from its neighbor molecules.

 11. Do you observe that some of the postulates of the kinetic molecular concept of gases are faulty? Point out the one's postulates.


 (i) The actual amount of fueloline molecules is negligible in the assessment of the amount of the vessel.
 (ii) There are not any forces of attraction to a number of the molecules of a fueloline.


 Both the postulates are correct at low stress and immoderate temperature and people postulates end up wrong at low temperatures and immoderate stress.

 It is important to account for the actual amount and mutual points of interest of molecules. This method is completed through the manner of the method of Van der Waal.

 12. All gases can be liquefied through manner of the method of Linde’s Method except Hydrogen and Helium, deliver a reason behind why?


 Hydrogen and helium can’t be liquefied through the manner of a method of Linde’s Method because of the truth their sizes are so small and that they've very low polarizability. Due to the one's factors even as immoderate stress is executed they professional very plenty much less intermolecular forces. When stress is released suddenly, they don’t liquefy due to the absence of sufficient intermolecular forces. So that you may liquefy them, their temperature has to hold toward absolute zero.

 13. CO2 fueloline deviates in massive element from the general fueloline equation at 0°C, but an excessive amount of much less amount at 100°C.


 The period of CO2 is huge so at 0°C the forces of attraction in CO2 end up dominant so it deviates in massive element from the general fueloline equation. But plenty much less amount at 100°C because of the truth at immoderate temperature, kinetic electricity may even end up immoderate due to which forces of attraction in CO2 molecule end up plenty much less dominant.

 14. Why is a CO2(31. 1°C) of crucial temperature plenty much less than NH3 (132. four°C)?


 The crucial temperature for CO2 is plenty much less than NH3 because of the truth in NH3 hydrogen bonding enjoys stronger intermolecular forces even as in CO2 there may be no hydrogen bonding. So stronger the intermolecular forces then higher the crucial temperature. Moreover, the dimensions of the CO2 are extra than NH3. But the absence of hydrogen bonding in CO2 makes its crucial temperature plenty much less than NH3.

 15. Why do gases show non-best behavior at low temperatures and immoderate stress?


 Gases are best most effective at low stress and immoderate temperature and end up non-best at low temperature and immoderate stress. Actually, low temperature and immoderate stress end up accountable for the advent of forces of attraction, and moreover, the actual amount does now not remain negligible. And most effective non-best gases show forces of attraction amongst them.

 16. The stress of NH3 fueloline at given conditions (say 20 atm stress and room temperature) is plenty much less as calculated through manner of the method of Van der Waals equation than that calculated through manner of the method of the general fueloline equation.


 NH3 is a polar or non-best fueloline. It has attractive forces among its molecules which give plenty much less price of stress.


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